Let us define:-
Ng = No. of good events in the bad spill. Nb = No. of bad events expected if the "hadronic fraction" had not changed. Ne = No. of extra bad events due to the altered spill condtions. T = Dead time due a single event. S = Total spill length
The "hadronic fraction" for this spill is defined as:-
HF = Ng/(Ng+Nb+Ne) (1)
For a good spill at the same beam intensity we would have expected a hadronic
fraction given by:-
HF' = Ng/(Ng+Nb) (2)
We can also define the fractional dead time for the spill as follows:-
DT = T.(Ng+Nb+Ne)/S
=> T/S = DT/(Ng+Nb+Ne) (3)
Since, for fixed spill conditions, the number of good events obtained is proportional to the length of the spill, then the reduction in good events is given by:-
R = (S - T.Ne)/S
= 1 - (T/S).Ne
= 1 - DT.Ne/(Ng+Nb+Ne) from (3)
= 1 - DT.HF.Ne/Ng
Rearranging equation (1) we find :-
1/HF = (Ng+Nb+Ne)/Ng
= (Ng+Nb)/Ng + Ne/Ng
= 1/HF' + Ne/Ng from (2)
=> Ne/Ng = 1/HF - 1/HF'
= (HF'-HF)/(HF.HF')
Substituting this result into the expression for R gives:-
R = 1 - (HF'-HF).DT/HF'